Guys its just a simple weighted average,
4m represents 20% of the hole length so multiply each 4m intersection by 20%
6.19x0.2=1.238
2.8*0.2=0.56
Add the results together = 1.798
The remaining 60% of the hole would need to have a grade of -0.26g/t for the maths to work.
i.e. 1.64-1.798 = -0.158
0.158/0.6 = -0.26
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